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Question

Arrange the compounds I, II and III in decreasing order of their heats of combustion:

II > I > III
I > II > III
III > II > I
III > I > II

A

III > II > I

B

II > I > III

C

I > II > III

D

III > I > II

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Solution

Verified by Toppr

High ring strain will have less heat of combustion.
Order of heat of combustion: $I I I > I I > I$ , because ring strain is in the order $I > I I > I I I$ i.e. $5 -$ membered ring strain is highest and as result it will have the lowest heat of combustion.

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