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Question

As shown in Fig, a dust particle with mass m=5.0×109kg and charge q0= 2.0 n C starts from rest at point a and moves in a straight line to point b. What is its speed v at point b?
155858_7a786e2405d94f4c8a2b4554f82e48bb.png
  1. 26 ms1
  2. 34 ms1
  3. 46 m s1
  4. 14 m s1

A
46 m s1
B
26 ms1
C
34 ms1
D
14 m s1
Solution
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There is no external force so apply conservation of mechanical energy between points a and b
initially particle is at rest so kinetic energy at point a is zero
(KE+PE)a=(KE+PE)b
0+k(3×109)q00.01k(3×109)q00.02=12mv2+k(3×109)q00.02k(3×109)qo0.01
Put the values and get v=1215=46ms1

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