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Question

As shown in the figure, charges +q and -q are placed at the vertices B and C of an isosceles triangle. The potential at the vertex A is
1218523_fd5de3786ebd4277a532e0ff56da1669.png
  1. 14πε0.2qa2+b2
  2. 14πε0.qa2+b2
  3. 14πε0.(q)a2+b2
  4. zero

A
14πε0.(q)a2+b2
B
14πε0.qa2+b2
C
14πε0.2qa2+b2
D
zero
Solution
Verified by Toppr

VA=0
it is equidistance from positive and negative charge of equal magnitude.
Hence, option (D) is correct.

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