Assume that each diode as shown in the figure has a forward bias resistance of $50\Omega$ and an infinite reverse bias resistance. The current through the resistance $150\Omega$ is:

The circuit is as shown as image 1.
As the lower diode attached to $100\Omega$ resistance is in reversed biased so, it is non-conducting.
Now, the circuit can be redrawn as image 2.
$\therefore$ Current through the circuit, $I=\frac{V}{R}$$=\frac{10}{250}=0.04A$