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- 2π√q1q4πε0a3m
- 2π√4πε0a3mq1q
- π2π√q1q4πε0q3m
- none of these

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Solution

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−q1E=F=mf=−q1qx4πε0(x2+a2)3/2 as x << a, neglecting

x2 as compared to acceleration, f=−q1q2x4πε0a3m

Comparing it with f=ω2x

ω√q1q4πε0a3m or T=2π√4πε0a3mq1q

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