0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A steel wire 2 m long is suspended from the ceiling. When a mass is hung at its lower end, the increase in length recorded is 1 cm. Determine the strain in the wire.
  1. 5×103
  2. 65×103
  3. 6×103
  4. 7×103

A
6×103
B
5×103
C
65×103
D
7×103
Solution
Verified by Toppr

Strain=LL=0.01m2m
=0.01×0.5
=0.005
=5×103

Was this answer helpful?
2
Similar Questions
Q1
A steel wire 2 m long is suspended from the ceiling. When a mass is hung at its lower end, the increase in length recorded is 1 cm. Determine the strain in the wire.
View Solution
Q2
A steel wire 2 m long is suspended from the ceiling. When a mass is hung at its lower end, the increase in length recorded is 1 cm. Determine the strain in the wire.
View Solution
Q3
A light rod of length 2m is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and is of cross-section 0.1cm2 and the other of brass of cross-section 0.2cm2. At which distance a weight may be hung along the rod, in order to produce equal strains in both the wires?
(Ysteel=2×1011Nm2,Ybrass=1×1011Nm2)
View Solution
Q4
A mass of 2.5 kg is hung on a steel wire. This increase 0.25 cm in its length. Determine the work done to pull the wire. (g=10 m/s2)
View Solution
Q5
A light rod of length 2.00 m is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel of cross-section 103 m2 and the other is of brass of cross-section 2×103 m2. Find out the position along the rod at which a weight may be hung to produce equal stress in both the wires.

Given:
Ysteel=2×1011 N/m2
Ybrass=1011 N/m2

View Solution