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# At 1000C and 1 atm, if the density of liquid water is 1.0 g cm−3 and that of water vapour is 0.0006 g cm−3, then the volume occupied by water molecules in one litre of steam at that temperature is :6 cm360 cm30.6 cm30.06 cm3

A
6 cm3
B
60 cm3
C
0.6 cm3
D
0.06 cm3
Solution
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#### Density of liquid water =1gcm−3Density of water vapour =0.0006gcm−3Mass of 1000 ml stream =1000×0.0006=0.6g∵ Volume of liquid water =mass of 1000ml streamdensity of liquid waterV=0.6g1 g.cm−3V=0.6cm3∴ The answer is option C.

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