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At 1000C and 1 atm, if the density of liquid water is 1.0 g cm−3 and that of water vapour is 0.0006 g cm−3, then the volume occupied by water molecules in one litre of steam at that temperature is :

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Solution

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Density of water vapour =0.0006gcm−3

Mass of 1000 ml stream =1000×0.0006=0.6g

∵ Volume of liquid water =mass of 1000ml streamdensity of liquid water

V=0.6g1 g.cm−3

V=0.6cm3

∴ The answer is option C.

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