At 25∘C, the molar conductances at infinite dilution for the strong electrolytes NaOH,NaCl and BaCl2 are 248×10−4,126×10−4 and 280×10−4Sm2mol−1 respectively, λ∘mBa(OH)2 in Sm2mol−1 is
52.4×104
4.2×104
262×104
524×104
A
52.4×104
B
524×104
C
262×104
D
4.2×104
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Solution
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The correct option is B524×104 BaCl2+2NaOH→Ba(OH)2+2NaCl λ∞mBa(OH)2=λ∞mBaCl2+2λ∞mNaOH−2λ∞mNaCl =280×10−4+2×248×10−4−2×126×10−4 =(280+496−252)×10−4 =524×10−4Sm2mol−1.
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Q1
At 25∘C, the molar conductances at infinite dilution for the strong electrolytes NaOH,NaCl and BaCl2 are 248×10−4,126×10−4 and 280×10−4Sm2mol−1 respectively. ∧∘mBa(OH)2 in Sm2mol−1 is :
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Q2
At 25∘C, the molar conductances at infinite dilution for the strong electrolytes NaOH,NaCl and BaCl2 are 248×10−4,126×10−4 and 280×10−4Sm2mol−1 respectively, λ∘mBa(OH)2 in Sm2mol−1 is
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