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Standard XII
Chemistry
Introduction and Degree of Hydrolysis
Question
At
90
o
C
, pure water has
[
H
3
O
+
]
=
10
−
6
m on the value of
k
w
at this temperature is :
10
−
12
10
−
6
10
−
13
10
−
14
A
10
−
12
B
10
−
6
C
10
−
13
D
10
−
14
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Solution
Verified by Toppr
Given :- concentration of
H
3
O
+
=
10
−
6
m
o
l
/
L
Ionization reaction of
H
2
O
is :-
H
2
O
⇌
H
+
+
O
H
−
K
=
[
H
+
]
[
O
H
−
]
[
H
2
O
]
⇒
K
×
[
H
2
O
]
=
[
H
+
]
[
O
H
−
]
∴
K
w
=
[
H
+
]
[
O
H
−
]
[
H
+
]
=
[
O
H
−
]
=
10
−
6
m
o
l
/
6
(
∴
it mentioned that it is pure water)
K
w
=
[
H
+
]
[
O
H
−
]
=
10
−
6
×
10
−
6
=
10
−
12
∴
Ans is B)
10
−
12
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, pure water has
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H
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10
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