At a given instant, say t = 0, two radioactive substances A and B have equal activities. The ratio RBRA of their activities after time t itself decays with time t as e−3t. If the half-life of A is ln2, the half-life of B is:
Open in App
Verified by Toppr
Half life of A=ln2 t1/2=ℓn2λ λA=1 at t=0RA=RB NAe−λAT=NBe−λBT NA=NB at t = 0 at t= t RBRA=N0e−λtBN0e−λtA e−(λB−λA)t=e−3t λB−λA=3 λB=3+λA=4 t1/2=ℓn2λB=ℓn24
Was this answer helpful?
A radioactive nucleus A with a half-life T, decays into a nucleus B. At t=0, there is no nucleus B. At some time t, the ratio of the number of B to that of A is 0.3. Then, t is given by:
Two radioactive sample A and B have half T1 and T2(T1>T2) respectively. At T=0, the activity of a B was twice the activity of A. Their activity will become equal after a time :
Samples of two radioactive nuclides, X and Y, each have equal activity A at time t=0.X has a half-life of 24 years and Y a half-life of 16 years. The samples are mixed together. What will be the total activity of the mixture at t=48 years?
A radioactive element X with half life 2 h decays giving a stable element Y. After a time t, ratio of X and Y atoms is 1:16. Time t is?
Two radioactive samples A and B have half lives T1andT2(T1>T2) respectively. At t=0, the activity of B was twice the activity of A. Their activity will become equal after a time