At a hydroelectric power plant- the water pressure is a height of 300 m and the water flow available is 100 m-3-s-1- If the turbine generator efficiency is 60- estimate the electric power available from the plant -g - 9-8 ms-2- -

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Toppr Admin · Accepted Answer

The power generated is P-mgh-x3C1-V-xD7-gh-1000-xD7-100-xD7-9-8-xD7-300-294MWThe power available is P-0-6-xD7-1000-xD7-100-xD7-9-8-xD7-300-176-4MW

At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 $m^{3} s^{- 1}$ . If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 $m s^{- 2}$ ).

The power generated is $P = m g h = ρ V \times g h = 1000 \times 100 \times 9.8 \times 300 = 294 M W$
The power available is $P = 0.6 \times 1000 \times 100 \times 9.8 \times 300 = 176.4 M W$

At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m3s−1. If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8ms−2 ).

The power generated is P=mgh=ρV×gh=1000×100×9.8×300=294MWThe power available is P=0.6×1000×100×9.8×300=176.4MW

At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 $m^{3} s^{- 1}$ . If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 $m s^{- 2}$ ).

The power generated is $P = m g h = ρ V \times g h = 1000 \times 100 \times 9.8 \times 300 = 294 M W$
The power available is $P = 0.6 \times 1000 \times 100 \times 9.8 \times 300 = 176.4 M W$