At a place the value of BH and BV are 0.4×10−4and 0.3×10−4respectively. The resultant earths magnetic field is :
Open in App
Verified by Toppr
Was this answer helpful?
The magnetic field at the centre of the circular coil carrying current of 4A is
Two concentric coils X and Y of radii 16 cm and 10 cm lie in the same vertical plane containing N-S direction. X has 20 turns and carries 16 A. Y has 25 turns and carries 18 A. X has current in anticlockwise direction and Y has current in clockwise direction for an observer, looking at the coils facing the west. The magnitude of net magnetic field at their common centre is
A 50 turn closely wound circular coil of radius 12 cm carries a current of 2.4 A, the field at center of coil is.
A circular coil of radius 8.8 cm has 10 turns, a current of 1.0 A is passing through it. Find the resultant field at its centre when the plane of the coil is vertical and perpendicular to the magnetic meridian. The horizontal component of the earth’s magnetic induction =BH=0.4×10−4T,BV=0
At a place , the horizontal and vertical components of the earth's magnetic field are 0.4×10−4Tand0.3×10−4T respectively. The resultant earth's magnetic field will be