At a place the value of BH and BV are 0-4-10-4and 0-3-10-4respectively- The resultant earths magnetic field is -

Solve

Guides

Question

At a place the value of $B_{H}$ and $B_{V}$ are $0.4 \times 10^{- 4}$ and $0.3 \times 10^{- 4}$ respectively. The resultant earths magnetic field is :

0.5 \times 10^{- 4} T

10^{- 4} T

2 \times 10^{- 4} T

5 \times 10^{- 4} T

Open in App

Solution

Verified by Toppr

$I = \sqrt{B {_{H}}^{2} + B {_{V}}^{2}}$

Was this answer helpful?

Similar Questions

The magnetic field at the centre of the circular coil carrying current of 4A is

View Solution

Two concentric coils X and Y of radii 16 cm and 10 cm lie in the same vertical plane containing N-S direction. X has 20 turns and carries 16 A. Y has 25 turns and carries 18 A. X has current in anticlockwise direction and Y has current in clockwise direction for an observer, looking at the coils facing the west. The magnitude of net magnetic field at their common centre is

View Solution

A 50 turn closely wound circular coil of radius 12 cm carries a current of 2.4 A, the field at center of coil is.

View Solution

A circular coil of radius $8.8$ cm has $10$ turns, a current of $1.0$ A is passing through it. Find the resultant field at its centre when the plane of the coil is vertical and perpendicular to the magnetic meridian. The horizontal component of the earth’s magnetic induction $= B_{H} = 0.4 \times 10^{- 4} T, B_{V} = 0$

View Solution

At a place , the horizontal and vertical components of the earth's magnetic field are $0.4 \times 10^{- 4} T and 0.3 \times 10^{- 4} T$ respectively. The resultant earth's magnetic field will be

View Solution

Solve

Guides

At a place the value of BH and BV are 0.4×10−4and 0.3×10−4respectively. The resultant earths magnetic field is :

I=√BH2+BV2

At a place the value of $B_{H}$ and $B_{V}$ are $0.4 \times 10^{- 4}$ and $0.3 \times 10^{- 4}$ respectively. The resultant earths magnetic field is :

$I = \sqrt{B {_{H}}^{2} + B {_{V}}^{2}}$