At given instant of time two particles are having the position vectors 4^i−4^j+7^k and 2^i+2^j+5^k m respectively. If the velocity of the first particle is 0.4^i m/s, the velocity of second particle in m/s if they collide after 10 sec is
6(^i−^j+1√5^k)
0.6(^i−^j+^k3)
0.6(^i+^j+^k3)
0.6(^i+^j−^k3)
A
0.6(^i+^j−^k3)
B
6(^i−^j+1√5^k)
C
0.6(^i−^j+^k3)
D
0.6(^i+^j+^k3)
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Solution
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After 10s, co-ordinates of particle A is: →rA=4^i−4^j+7^k+0.4^i×10 Co-ordinates of particle B is→rB=2^i+2^j+5^k+→vA×10=4^i−4^j+7^k+0.4^i×10 →rA=→rB ⇒2^i+2^j+5^k+→vA×10=8^i−4^j+7^k
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