At room temperature (27.0oC) the resistance of a heating element is 100Ω . What is the temperature of the element if the resistance is found to be 117Ω, given that the temperature coefficient of the material of the resistor is 1.70×10−4C−1.
Step 1: Relation between value of resistance and temperature
R=R0[1+α(T−T0)]
Step 1: Temperature calculation
Let T is the increased temperature of the element, putting all the values in the formula to find T
T0=27oC, R0=100Ω, R=117Ω, α=1.70×10−4 oC−1
⇒117=100[1+1.7×10−4(T−27)]
⇒T=1027oC