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Question

At room temperature, copper has free electron density of 8.4×1028m3. The electron drift velocity in a copper conductor of cross-sectional area of 106m2 and carrying a current of 5.4 A, will be
  1. 0.4 ms1
  2. 4 cms1
  3. 0.4 mms1
  4. 4 ms1

A
4 ms1
B
4 cms1
C
0.4 mms1
D
0.4 ms1
Solution
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Current density and drift velocity are related by:
J=nevdI=nAevd
Substituting the values, we get:
vd=InAe=5.48.4×1028×106×1.6×1019=4×104 m/s

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