At some planet -g- is 1-96 m-s-2- If it is safe to jump from a height of 2m on earth- then what should be corresponding safe height jumping on that planet5m20m2m10m

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Toppr Admin · Accepted Answer

At earth- -xA0- ge-9-8m-s2he-2m -xA0-At other planet- -xA0- gp-1-96h-x27F9-gpge-15Now at some planet g reduces by 5 times- thus safe height will increases by 5 times-Hence -xA0-h-5-xD7-2-10m

At some planet ' $g$ ' is $1.96 m / s^{2}$ . If it is safe to jump from a height of $2 m$ on earth, then what should be corresponding safe height for jumping on that planet
$5 m$
$20 m$
$2 m$
$10 m$

At earth, $g_{e} = 9.8 m / s^{2} h_{e} = 2 m$
At other planet, $g_{p} = 1.96 h = ?$
$⟹ \frac{g_{p}}{g_{e}} = \frac{1}{5}$
Now at some planet g reduces by $5$ times, thus safe height will increases by $5$ times.
Hence $h = 5 \times 2 = 10 m$

At some planet 'g' is 1.96m/s2. If it is safe to jump from a height of 2m on earth, then what should be corresponding safe height for jumping on that planet5m20m2m10m

At earth, ge=9.8m/s2he=2m At other planet, gp=1.96h=?⟹gpge=15Now at some planet g reduces by 5 times, thus safe height will increases by 5 times.Hence h=5×2=10m

At some planet ' $g$ ' is $1.96 m / s^{2}$ . If it is safe to jump from a height of $2 m$ on earth, then what should be corresponding safe height for jumping on that planet
$5 m$
$20 m$
$2 m$
$10 m$

At earth, $g_{e} = 9.8 m / s^{2} h_{e} = 2 m$
At other planet, $g_{p} = 1.96 h = ?$
$⟹ \frac{g_{p}}{g_{e}} = \frac{1}{5}$
Now at some planet g reduces by $5$ times, thus safe height will increases by $5$ times.
Hence $h = 5 \times 2 = 10 m$