At sun rise of sunset, the sun looks more red than at mid-day because

Question

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Answer 1

$I \propto \frac{1}{λ ^{4}}$
According to Rayleigh’s law of scattering, intensity scattered is inversely proportional to the forth power of wavelength. So red is least scattered and sun appears Red.

Answer 2

I \propto \frac{1}{λ ^{4}}

According to Rayleigh’s law of scattering, intensity scattered is inversely proportional to the forth power of wavelength. So red is least scattered and sun appears Red.

At sun rise of sunset, the sun looks more red than at mid-day because

The sun is hottest at these times

Of the scattering of light

Of the effects of refraction

Of the effects of diffraction

$I \propto \frac{1}{λ ^{4}}$
According to Rayleigh’s law of scattering, intensity scattered is inversely proportional to the forth power of wavelength. So red is least scattered and sun appears Red.

The setting sun appears to be red.

Scattering of light is directly proportional to the wavelength.

The setting sun appears to be red.

Rising and setting sun appears to be reddish because:

The sun appears red at the time of sun-rise and sun-set. This is because:

Why does sun appear reddish at sunrise and sunset?

The rising and setting of sun appear red because of :

Revise with Concepts

Scattering of Light

At sun rise of sunset, the sun looks more red than at mid-day because

The sun is hottest at these times

Of the scattering of light

Of the effects of refraction

Of the effects of diffraction

I∝λ41​According to Rayleigh’s law of scattering, intensity scattered is inversely proportional to the forth power of wavelength. So red is least scattered and sun appears Red.

The setting sun appears to be red.

Scattering of light is directly proportional to the wavelength.

The setting sun appears to be red.

Rising and setting sun appears to be reddish because:

The sun appears red at the time of sun-rise and sun-set. This is because:

Why does sun appear reddish at sunrise and sunset?

The rising and setting of sun appear red because of :

Revise with Concepts

Scattering of Light

$I \propto \frac{1}{λ ^{4}}$
According to Rayleigh’s law of scattering, intensity scattered is inversely proportional to the forth power of wavelength. So red is least scattered and sun appears Red.