Question

# At what distance above the surface of earth, the gravitational force will be reduced by 10%, if the radius of earth is 6370 Km.

A
750Km
B
650Km
C
450Km
D
344Km
Solution
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#### Gravitational force on the earth surface,FGs=GMmR2Gravitational force at a height 'h' above,FGh=GMm(R+h)2G.T. FGh=90100(FGS)⇒GMm(R+h)2=910(GMmR2)⇒R+h=√109(R)⇒6370+h=3.1623(6370)⇒h=0.162×63703=344 km

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