Solve

Guides

Question

At what distance above the surface of earth, the gravitational force will be reduced by 10%, if the radius of earth is 6370 Km.

Open in App

Solution

Verified by Toppr

Gravitational force on the earth surface,

FGs=GMmR2

Gravitational force at a height 'h' above,

FGh=GMm(R+h)2

G.T. FGh=90100(FGS)

⇒GMm(R+h)2=910(GMmR2)

⇒R+h=√109(R)

⇒6370+h=3.1623(6370)

⇒h=0.162×63703=344 km

Was this answer helpful?

1