Atomic mass of boron is 10-81 amu- It has two isotopes with 80- and 20- abundance respectively- The atomic mass of one isotope is 11- the mass of other isotope is-21-8210-8111-0110-05

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Atomic mass of Boron -10-81duppose mass of other isotope-mmass of one isotope -1111-xD7-80-m-xD7-20-10-8111-xD7-80-m-xD7-20100-10-81880-20m-108120-xA0-m-1081-x2212-880-201m-20120-10-05

Atomic mass of boron is 10.81 amu. It has two isotopes with 80% and 20% abundance respectively. The atomic mass of one isotope is 11, the mass of other isotope is:
21.82
10.81
11.01
10.05

Atomic mass of Boron $= 10.81$
duppose mass of other isotope $= m$
mass of one isotope $= 11$
$11 \times 80 % + m \times 20 % = 10.81$
$\frac{11 \times 80 + m \times 20}{100} = 10.81$
$880 + 20 m = 1081$
$20 m = 1081 - 880 = 201$
$m = \frac{201}{20} = 10.05$

Atomic mass of boron is 10.81 amu. It has two isotopes with 80% and 20% abundance respectively. The atomic mass of one isotope is 11, the mass of other isotope is:21.8210.8111.0110.05

Atomic mass of Boron =10.81duppose mass of other isotope=mmass of one isotope =1111×80%+m×20%=10.8111×80+m×20100=10.81880+20m=108120 m=1081−880=201m=20120=10.05

Atomic mass of boron is 10.81 amu. It has two isotopes with 80% and 20% abundance respectively. The atomic mass of one isotope is 11, the mass of other isotope is:
21.82
10.81
11.01
10.05

Atomic mass of Boron $= 10.81$
duppose mass of other isotope $= m$
mass of one isotope $= 11$
$11 \times 80 % + m \times 20 % = 10.81$
$\frac{11 \times 80 + m \times 20}{100} = 10.81$
$880 + 20 m = 1081$
$20 m = 1081 - 880 = 201$
$m = \frac{201}{20} = 10.05$