The odometer of a car reads $57321.0 k m$ when the clock shows the time 8:30 AM. The distance moved by car if, at 8:50 AM, the odometer reading has changed to $57336.0 k m$ and also the speed will be:

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Answer 1

Time from $8.30$ $A M$ to $8.50$ $A M$ = $20$ $m i n$
$20 m i n = (20 / 60) h = (1 / 3) h$

(a) Distance covered = Second reading - First reading = $57336.0$ $k m$ - $57321.0$ $k m$ = $15$ $k m$
(b) $S p e e d = \frac{D i s t a n c e}{T i m e}$ = $\frac{1 5}{1 / 3}$ = $45 k m / h$

Answer 2

Time from $8.30$ $A M$ to $8.50$ $A M$ = $20$ $m i n$

$20 m i n = (20 / 60) h = (1 / 3) h$

(a) Distance covered = Second reading - First reading = $57336.0$ $k m$ - $57321.0$ $k m$ = $15$ $k m$

(b) $S p e e d = \frac{D i s t a n c e}{T i m e}$ = $\frac{1 5}{1 / 3}$ = $45 k m / h$

The odometer of a car reads $57321.0 k m$ when the clock shows the time 8:30 AM. The distance moved by car if, at 8:50 AM, the odometer reading has changed to $57336.0 k m$ and also the speed will be:

$15 k m, 45 k m / h$

$10 k m,$ $45 k m / h$

$15 k m,$ $55 k m / h$

$20 k m,$ $45 k m / h$

Time from $8.30$ $A M$ to $8.50$ $A M$ = $20$ $m i n$
$20 m i n = (20 / 60) h = (1 / 3) h$

(a) Distance covered = Second reading - First reading = $57336.0$ $k m$ - $57321.0$ $k m$ = $15$ $k m$
(b) $S p e e d = \frac{D i s t a n c e}{T i m e}$ = $\frac{1 5}{1 / 3}$ = $45 k m / h$

A car travels a distance of 15 km in 20 minutes. Find the speed of the car in $m s^{- 1}$

Give Reasons for the following:
If the reading on the odometer of a vehicle in the beginning of a trip and after $40$ minutes were $1048 k m$ and $1096 k m$ respectively, will the reading on the speedometer show this velocity where the vehicle is moving? Support your answer with reason.

Change the speed of $6 m / s$ into $k m / h$

The odometer of a car reads $57321.0 k m$ when the clock shows the time $08 : 30$ AM. What is the distance moved by the car, if at $08 : 50 A M$ , the odometer reading has changed to $57336.0 k m$ ?

A car moving on a straight path covers a distance of $1 k m$ due to east in $100 s$ . What is the speed of the car?

Revise with Concepts

Speed

Understanding Uniform and Non-Uniform Motion

Basic Introduction to Velocity

Average Speed and Average Velocity

Instantaneous Velocity and Instantaneous Speed

Velocity - Time Graph

The odometer of a car reads 57321.0 km when the clock shows the time 8:30 AM. The distance moved by car if, at 8:50 AM, the odometer reading has changed to 57336.0 km and also the speed will be:

15 km, 45km/h

10km, 45km/h

15km, 55km/h

20km, 45km/h

Time from 8.30 AM to 8.50 AM = 20 min 20min=(20/60)h=(1/3)h =2060h=13h(a) Distance covered = Second reading - First reading = 57336.0 km - 57321.0 km = 15 km(b) Speed=TimeDistance​=1/315​=45km/h

A car travels a distance of 15 km in 20 minutes. Find the speed of the car in ms−1

Give Reasons for the following: If the reading on the odometer of a vehicle in the beginning of a trip and after 40 minutes were 1048km and 1096km respectively, will the reading on the speedometer show this velocity where the vehicle is moving? Support your answer with reason.

Change the speed of 6 m/s into km/h

The odometer of a car reads 57321.0km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50AM, the odometer reading has changed to 57336.0km?

A car moving on a straight path covers a distance of 1 km due to east in 100 s. What is the speed of the car?

Revise with Concepts

Speed

Understanding Uniform and Non-Uniform Motion

Basic Introduction to Velocity

Average Speed and Average Velocity

Instantaneous Velocity and Instantaneous Speed

Velocity - Time Graph

The odometer of a car reads $57321.0 k m$ when the clock shows the time 8:30 AM. The distance moved by car if, at 8:50 AM, the odometer reading has changed to $57336.0 k m$ and also the speed will be:

$15 k m, 45 k m / h$

$10 k m,$ $45 k m / h$

$15 k m,$ $55 k m / h$

$20 k m,$ $45 k m / h$

Time from $8.30$ $A M$ to $8.50$ $A M$ = $20$ $m i n$
$20 m i n = (20 / 60) h = (1 / 3) h$

(a) Distance covered = Second reading - First reading = $57336.0$ $k m$ - $57321.0$ $k m$ = $15$ $k m$
(b) $S p e e d = \frac{D i s t a n c e}{T i m e}$ = $\frac{1 5}{1 / 3}$ = $45 k m / h$

A car travels a distance of 15 km in 20 minutes. Find the speed of the car in $m s^{- 1}$

Give Reasons for the following:
If the reading on the odometer of a vehicle in the beginning of a trip and after $40$ minutes were $1048 k m$ and $1096 k m$ respectively, will the reading on the speedometer show this velocity where the vehicle is moving? Support your answer with reason.

Change the speed of $6 m / s$ into $k m / h$

The odometer of a car reads $57321.0 k m$ when the clock shows the time $08 : 30$ AM. What is the distance moved by the car, if at $08 : 50 A M$ , the odometer reading has changed to $57336.0 k m$ ?

A car moving on a straight path covers a distance of $1 k m$ due to east in $100 s$ . What is the speed of the car?