Babubhai borrows Rs- 4000 and agrees to repay with a total interest of Rs- 500 in 10 installations- each instalment being than the preceding instalment by Rs- 10- What should be the first and last installment-

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Toppr Admin · Accepted Answer

The installments are in A-P- with difference 10-Hence-a-a-x2212-10-a-x2212-20-a-x2212-30-a-x2212-90-50010-a-a-x2212-90-2-5002a-x2212-90-100a-95

Babubhai borrows Rs. $4000$ and agrees to repay with a total interest of Rs. $500$ in $10$ installations, each instalment being less than the preceding instalment by Rs. $10$ . What should be the first and last installment?

The installments are in A.P. with difference 10.
Hence,
$a + a - 10 + a - 20 + a - 30 + . . . . . + a - 90 = 500$
$\frac{10 (a + a - 90)}{2} = 500$
$2 a - 90 = 100$
$a = 95$

Babubhai borrows Rs. 4000 and agrees to repay with a total interest of Rs. 500 in 10 installations, each instalment being less than the preceding instalment by Rs. 10. What should be the first and last installment?

The installments are in A.P. with difference 10.Hence,a+a−10+a−20+a−30+.....+a−90=50010(a+a−90)2=5002a−90=100a=95

Babubhai borrows Rs. $4000$ and agrees to repay with a total interest of Rs. $500$ in $10$ installations, each instalment being less than the preceding instalment by Rs. $10$ . What should be the first and last installment?

The installments are in A.P. with difference 10.
Hence,
$a + a - 10 + a - 20 + a - 30 + . . . . . + a - 90 = 500$
$\frac{10 (a + a - 90)}{2} = 500$
$2 a - 90 = 100$
$a = 95$