Balance equations the following reactions -An addition reaction of ethyne with hydrogen in presence of catalyst gives -CH-2- CH-2-C-2-H-6-C-3-H-8-both A and B

Question

Toppr Admin · Accepted Answer

Ethyne undergoes catalytic hydrogenation which is an addition reaction , to form ethene which on further addition forms ethane.
$C H \equiv C H H_{2} - ---- \to N i, 150^{\circ} C C H_{2} = C H_{2} H_{2} - ---- \to N i, 150^{\circ} C C_{2} H_{6}$

Reactabts $(A)$	Products $(B)$	Name of the reaction $(C)$
$C H_{3} - C H_{3} + C l_{2}$	$C O_{2} + H_{2} O$	Addition reaction
$C_{2} H_{6} + O_{2}$	$C H_{2} = C H_{2}$	Thermal cracking
$_{n} C H_{2} = C H_{2}$	$C H_{2} = C H_{2} + C H_{4}$	Substitution reactions
$C H_{3} - C H_{2} - C H_{3}$	$C H_{3} - C H_{2} C l + H C l$	Polymerisation
$C H \equiv C H + H_{2}$	$[- C H_{2} - C H_{2} -]_{n}$	Combustion

Balance equations for the following reactions :An addition reaction of ethyne with hydrogen in presence of catalyst gives :CH2=CH2C2H6C3H8both A and B

Ethyne undergoes catalytic hydrogenation which is an addition reaction , to form ethene which on further addition forms ethane.CH≡CHH2−−−−−→Ni,150∘CCH2=CH2H2−−−−−→Ni,150∘CC2H6

Balance equations for the following reactions :
An addition reaction of ethyne with hydrogen in presence of catalyst gives :
$C H_{2} = C H_{2}$
$C_{2} H_{6}$
$C_{3} H_{8}$
both A and B

Ethyne undergoes catalytic hydrogenation which is an addition reaction , to form ethene which on further addition forms ethane.
$C H \equiv C H H_{2} - ---- \to N i, 150^{\circ} C C H_{2} = C H_{2} H_{2} - ---- \to N i, 150^{\circ} C C_{2} H_{6}$