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$B a (O H)_{2}$ is a strong base. The $p H$ of its 0.005 solution would be:
11.7
12
11.31
none of these

A

11.7

B

none of these

C

11.31

D

12

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Solution

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$p H$ of $0.005 M$ barium hydroxide
$p O H = - l o g (O H)$ to the base 10
$p O H = - l o g (0.005) = 2.3$
$p H = 14 - p O H = 14 - 2.3$
$p H = 11.7$

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