BD is a perpendicular bisector of AC.Which statement can NOT always be proven?
BD≅DC
AD≅CD
∠ADB≅∠CDB
△ABD≅△CBD
A
∠ADB≅∠CDB
B
AD≅CD
C
△ABD≅△CBD
D
BD≅DC
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Solution
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In △ABD and △BDC
AD=CD ...... D is the perpendicular bisector of AC
∠BDA=∠BDC=90∘
BD is the common side.
Triangles are congruent. SAS Postulate.
Hence the corresponding sides and angles are equal/congruent.
From the options, BD≅DC is incorrect as they are not the corresponding sides.
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