Bear a two-digit number in mind-Without disclosing it- cunstruct a puzzle create two algebraic relations between the two digits of the number and solve the puzzle-

Question

Toppr Admin · Accepted Answer

I am a number- tell my identity- three times of me- add fifty-xA0-You still need forty to have a triple century-Let the number be x-3x-50-40-3003x-300-x2212-903x-210x-70Hence- this is the answer-

Bear a two-digit number in mind.Without disclosing it, cunstruct a puzzle create two algebraic relations between the two digits of the number and solve the puzzle.

I am a number, tell my identity, three times of me, add fifty. You still need forty to have a triple century.

Let the number be $x .$
$\begin{matrix} (3 x + 50) + 40 & = 300 3 x & = 300 - 90 3 x & = 210 x & = 70 \end{matrix}$

Hence, this is the answer.

Bear a two-digit number in mind.Without disclosing it, cunstruct a puzzle create two algebraic relations between the two digits of the number and solve the puzzle.

I am a number, tell my identity, three times of me, add fifty. You still need forty to have a triple century.Let the number be x.(3x+50)+40=3003x=300−903x=210x=70Hence, this is the answer.

I am a number, tell my identity, three times of me, add fifty. You still need forty to have a triple century.

Let the number be $x .$
$\begin{matrix} (3 x + 50) + 40 & = 300 3 x & = 300 - 90 3 x & = 210 x & = 70 \end{matrix}$

Hence, this is the answer.