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Question

Beats are heard due Ito interference of two sound waves. The intensity of sound changes from maximum to minimum in 100 ms. Therefore, the difference in frequencies of the two waves is
2.5 Hz
10 Hz
5 Hz
20 Hz

A

20 Hz

B

10 Hz

C

5 Hz

D

2.5 Hz

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Solution

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Time period of the beats produced is the time interval during which the intensity changes from maximum to maximum.
Thus time period of the beats $T = 2 \times 100 m s = 200 \times 10^{- 2} s$
So, beat frequency $ν = \frac{1}{T} = \frac{1}{200 \times 10^{- 3}} = 5 H z$

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