The circumferences of circular faces of a frustum are
132 cm and
88 cm and its height is
24 cm. To find the curved surface area of the frustum complete the following activity.
(π=227 ).
circumference 1=2πr1=132r1=1322π=□ circumference 2=2πr2=88
r2=882π=□
slant height of frustum,
l=√h2+(r1−r2)2
slant height of frustum,
l=√h2+(r1−r2)2=√□2+□2=□cm
curved surface area of the frustum =π(r1+r2)l=π×□×□=□ sq.cm.