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Hardness of Water and Treatment

Question

Both temporary and permanent hardness is removed on boiling water with :-
$C a (O H)_{2}$
$N a_{2} C O_{3}$
$C a C O_{3}$
$C a O$

A

C a C O_{3}

B

C a (O H)_{2}

C

C a O

D

N a_{2} C O_{3}

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Solution

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Temporary hardness is removed by boiling water with $N a O H$ and $N a_{2} C O_{3}$ . $C a (H C O_{3})_{2} + 2 N a O H \to C a C O_{3} ↓ + N a_{2} C O_{3} + 2 H_{2} O$ Permanent hardness is removed by boiling water with sodium carbonate. $C a C l_{2} + N a_{2} C O_{3} \to C a C O_{3} ↓ + 2 N a C l$

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Both temporary and permanent hardness is removed on boiling water with :-

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Both the temporary and the permanent hardness of water is removed on boiling with:

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Q3

Following reaction is used to remove temporary hardness which is due to dissolved bicarbonates of

C a^{2 +}

and

M g^{2 +}

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C a (H C O_{3})_{2} + C a (O H)_{2} \to 2 C a C O_{3} ↓ + 2 H_{2} O

Actually lime (

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