$C_{6} H_{5} C O O H 2 . Δ 1 . N H_{3} P N a O B r Q 2 . h e a t t o 460 K 1 . C o n c . H_{2} S O_{4}^{'} R^{'}$
' $R$ ' is :

Name: C6H5COOH 2. Δ 1. NH3 P NaOBr Q 2. heat to 460K 1. Conc. H2SO4 'R' ' R ' is :
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Answer 1

$C_{6} H_{5} C O O H N H_{3} / Δ P C_{6} H_{5} CON H_{2} N a O B r Q C_{6} H_{5} N H_{2} C o n c . H_{2} S O_{4} R p - s u lp hani l i c a c i d$

R is $H_{2} N - C_{6} H_{4} - S O_{3} H$

Option D is correct

Answer 2

C_{6} H_{5} C O O H N H_{3} / Δ P C_{6} H_{5} CON H_{2} N a O B r Q C_{6} H_{5} N H_{2} C o n c . H_{2} S O_{4} R p - s u lp hani l i c a c i d

R is

H_{2} N - C_{6} H_{4} - S O_{3} H

Option D is correct

$C_{6} H_{5} C O O H 2 . Δ 1 . N H_{3} P N a O B r Q 2 . h e a t t o 460 K 1 . C o n c . H_{2} S O_{4}^{'} R^{'}$
' $R$ ' is :

sulphanilamide

$p$ -bromo sulphanilamide

$o$ -bromo sulphanilic acid

sulphanilic acid

Solution

$C_{6} H_{5} C O O H N H_{3} / Δ P C_{6} H_{5} CON H_{2} N a O B r Q C_{6} H_{5} N H_{2} C o n c . H_{2} S O_{4} R p - s u lp hani l i c a c i d$

R is $H_{2} N - C_{6} H_{4} - S O_{3} H$

Option D is correct

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C6​H5​COOH2. Δ1. NH3​​​P NaOBr ​Q2. heat to 460K1.Conc.H2​SO4​​​′R′ 'R' is :

sulphanilamide

p-bromo sulphanilamide

o-bromo sulphanilic acid

sulphanilic acid

C6​H5​COOHNH3​/Δ​PC6​H5​CONH2​​NaOBr​QC6​H5​NH2​​Conc.H2​SO4​​Rp−sulphanilic​ acid R is H2​N−C6​H4​−SO3​H Option D is correct

Video Explanation

Patterns of problems

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$C_{6} H_{5} C O O H 2 . Δ 1 . N H_{3} P N a O B r Q 2 . h e a t t o 460 K 1 . C o n c . H_{2} S O_{4}^{'} R^{'}$
' $R$ ' is :

$p$ -bromo sulphanilamide

$o$ -bromo sulphanilic acid

$C_{6} H_{5} C O O H N H_{3} / Δ P C_{6} H_{5} CON H_{2} N a O B r Q C_{6} H_{5} N H_{2} C o n c . H_{2} S O_{4} R p - s u lp hani l i c a c i d$

R is $H_{2} N - C_{6} H_{4} - S O_{3} H$

Option D is correct

What happens when?
Citric acid is refluxed with hydriodic acid

Complete the missing links (X) , (Y) and (Z) by making an appropriate choice.
$C H_{3} C O O H \to P B r_{3} / B r_{2} X \to K C N Y \to H_{3} O^{+} Z$

Identify the compounds $A$ , $B$ and $C$ :
(i) $C_{6} H_{5} C O O H P C l_{5} A H_{z} - P d / B a S O_{4} B K C N (a l c) d i s t i l C$
(ii) $H - C \equiv C - H H_{2} O d i l H_{2} S O_{4} + H_{g} S O_{4} A$ $H_{2} N i$ $B 140^{o} C c o n c H_{2} S O_{4} C$

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