C-6-H-5-NH-2-xrightarrow-NaNO-2-HCl- 0-o-C-X -xrightarrow-H-2-O- warm-YIn the above reaction- Y is-C-6-H-5-ClC-6-H-6-C-6-H-5-CHOC-6-H-5-OH

Question

Toppr Admin · Accepted Answer

C6H5NH2 gives benzene diazonium chloride -X- upon reaction with NaNO2 and HCl-xA0-The formed-xA0-benzene diazonium-xA0-chloride-xA0-X- gives-xA0-phenol -Y-xA0-in the presence of water-The reaction is as follows-Option C is correct-

$C_{6} H_{5} N H_{2} N a N O_{2} + H C l, 0^{o} C - ---------- \to X H_{2} O, w a r m - ------ \to Y$
In the above reaction, $Y$ is:

$C_{6} H_{5} C l$
$C_{6} H_{6}$
$C_{6} H_{5} C H O$
$C_{6} H_{5} O H$

$C_{6} H_{5} N H_{2}$ gives benzene diazonium chloride ( $X$ ) upon reaction with $N a N O_{2}$ and $H C l$ .

The formed benzene diazonium chloride ( $X$ ) gives phenol ( $Y$ ) in the presence of water.

The reaction is as follows:

Option C is correct.

C6H5NH2NaNO2+HCl,0oC−−−−−−−−−−−→XH2O,warm−−−−−−−→YIn the above reaction, Y is:C6H5ClC6H6C6H5CHOC6H5OH

C6H5NH2 gives benzene diazonium chloride (X) upon reaction with NaNO2 and HCl. The formed benzene diazonium chloride (X) gives phenol (Y) in the presence of water.The reaction is as follows:Option C is correct.

$C_{6} H_{5} N H_{2} N a N O_{2} + H C l, 0^{o} C - ---------- \to X H_{2} O, w a r m - ------ \to Y$
In the above reaction, $Y$ is:

$C_{6} H_{5} C l$
$C_{6} H_{6}$
$C_{6} H_{5} C H O$
$C_{6} H_{5} O H$

$C_{6} H_{5} N H_{2}$ gives benzene diazonium chloride ( $X$ ) upon reaction with $N a N O_{2}$ and $H C l$ .

The formed benzene diazonium chloride ( $X$ ) gives phenol ( $Y$ ) in the presence of water.

The reaction is as follows:

Option C is correct.