Ethyl alcohol forms CaCl2.XC2H5OH;MgCl2.YC2H5OH and CuSO4.ZC2H5OH when C2H5OH reacts with respective respective anhydrous salts. Then?
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Q3
CaCl2 + C2H5OH = CaCl2.xC2H5OH . Then 'x' is
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Q4
The dissolution of CaCl2⋅6H2O in a large volume of water is endothermic to the extent of 3.5Kcalmol−1. For the reaction, CaCl2(s)+6H2O(l)⟶CaCl2⋅6H2O(s) ΔH is −23.2Kcal. The heat of solution of anhydrous CaCl2 in large quantity of water will be:
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Q5
CaCl2+Be2CO3→CaCO3+BeCl3 I. Provided the reaction above, if 1.10g of CaCl2 and 0.85g of Be2CO3 will be the limiting reactant. II. The limiting reactant in a reaction will always be the reactant that has the lowest mass.