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Calculate AB

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Solution

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$A D = 2$ cm
$∠ A C D = 45^{\circ}$
Now, In $△ A D C$
$tan 45 = \frac{A D}{C D}$
$A D = C D = 2$
Since, $A D ∥ B C$ and $A B ∥ C D$
$A B C D$ is a parallelogram.
Hence, $A B = C D = 2$ cm

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