Calculate angular width of central maxima if λ=6000˚A,a=18×10−5cm :
28.40
38.90
300
2600
A
28.40
B
38.90
C
300
D
2600
Open in App
Solution
Verified by Toppr
Was this answer helpful?
15
Similar Questions
Q1
Calculate angular width of central maxima if λ=6000˚A,a=18×10−5cm :
View Solution
Q2
Calculate the semi-angular width of central maxima, if λ=6000˚A,a=18×10−5cm.
View Solution
Q3
What will be the angular width of central maxima in Fraunhoffer diffraction when light of wavelength 6000˚A is used and slit width is 12×10−5cm.
View Solution
Q4
Light of wavelength 6000∘A is incident normally on a single slit of width 24×10−5cm. Find out the angular position of second minimum from central maxima?
View Solution
Q5
A light of wavelength $$\lambda$$ is incident over a single slit of width $$24 \times 10 ^ { - 5 }$$maxima is $$30$$'. Value of $$ \lambda$$ will be - $$cm$$. The angular position of second minima from central maxima is $$30 ^ { \circ }$$. Value of $$\lambda$$ will be:-