Question

Calculate Impedance of the given ac circuit.

Answer 1

Potential difference across capacitance, $$V_{C} = X_{C}I$$

$$\therefore$$ Capacitive reactance,

$$X_{C} = \dfrac{V_{C}}{I} = \dfrac{40}{2} = 20\Omega$$

Resistance, $$R = \dfrac{V_{R}}{I} = \dfrac{30}{2} = 15\Omega$$

Impedance, $$Z = \sqrt{R^{2}+X_{C}^{2}} = \sqrt{(15)^{2}+(20)^{2}}=\sqrt{225+400}=\sqrt{625}\Omega=25\Omega$$