Question

Calculate pressure of gas whose molar mass is $29.3g/mol.$ having density $1.29kg/m^3$ at 273 K.

Answer 1

$PM=dRT$

Pressure, $P=\frac{dRT}{M}$ $[d=1.29kg/m^3=1.29\times {10}^{-3}g/c{m}^3=1.29\times {10}^{-3}g/Lit]$

$=\frac{(1.29\times {10}^{-3})\left(0.0821\right)\left(273\right)}{29.3}$ $[R=0.0821litatm/molK;T=273K]$

$=0.986\times {10}^{-3}atm$

$=98.6\times {10}^{-5}atm$