First, let us find the mass defect. The Beryllium nucleus contains 4 protons and 5 neutrons.
Mass of 4 protons =4×1.008=4.032u; Mass of 5 neutrons =5×1.009u=5.045u
Total mass of protons (4) and neutrons (5) =4.032+5.045=9.077u
Mass defect =9.077−9.012=0.065u
The mass defect converted into equivalent energy gives binding energy.
1u=931.5MeV
∴0.065u=0.065×931.5MeV=60.5475MeV
Binding energy per nucleon =BindingenergyNumberofnucleons=60.54759=6.7275MeV