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Question

Calculate the binding energy per nucleon for Beryllium 4Be9, its mass being 9.012 u. The masses of proton and neutron are 1.008u and 1.009u. (Take 1u=931.5MeV)
  1. 8.3636 MeV
  2. 7.2828 MeV
  3. 9.4444 MeV
  4. 6.7275 MeV

A
8.3636 MeV
B
9.4444 MeV
C
7.2828 MeV
D
6.7275 MeV
Solution
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First, let us find the mass defect. The Beryllium nucleus contains 4 protons and 5 neutrons.
Mass of 4 protons =4×1.008=4.032u; Mass of 5 neutrons =5×1.009u=5.045u
Total mass of protons (4) and neutrons (5) =4.032+5.045=9.077u
Mass defect =9.0779.012=0.065u
The mass defect converted into equivalent energy gives binding energy.
1u=931.5MeV
0.065u=0.065×931.5MeV=60.5475MeV
Binding energy per nucleon =BindingenergyNumberofnucleons=60.54759=6.7275MeV

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