A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d (as shown in Fig). The inner shell has total charge +2q and the outer shell has charge +4q. Calculate the electric field in terms of q and the distance r from the common centre of the two shells for: a<r<b.
Zero
14πε02qr2
−14πε06qr2
14πε0qr2
A
14πε02qr2
B
−14πε06qr2
C
14πε0qr2
D
Zero
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Solution
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There is no charge inside the surface a≤r<b since there is no charge inside the inner shell, therefore all the charge will be on outside surface and charge enclosed is zero, hence electric field will also be zero
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