Calculate the electrode potential a copper electrode dipped in a 0-1 M solution of copper sulphate 25-circ-C- The standard electrode potential of Cu-2-Cu system is 0-34 volt 298 K-

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We know that- Ered-E-x2218-red-0-0591nlog10-ion-Putting the values of E-x2218-red-0-34-xA0-V-n-2 and -Cu2-0-1MEred-0-34-0-05912log10-0-1-0-34-0-02955-xD7-x2212-1-0-34-x2212-0-02955-0-31045-xA0-volt-

Calculate the electrode potential at a copper electrode dipped in a $0.1 M$ solution of copper sulphate at $25^{\circ} C$ . The standard electrode potential of $C u^{2 +} / C u$ system is $0.34 v o l t$ at $298 K$ .

We know that, $E_{r e d} = E_{r e d}^{\circ} + \frac{0.0591}{n} {log}_{10} [i o n]$
Putting the values of $E_{r e d}^{\circ} = 0.34 V, n = 2$ and $[C u^{2 +}] = 0.1 M$
$E_{r e d} = 0.34 + \frac{0.0591}{2} {log}_{10} [0.1]$
$= 0.34 + 0.02955 \times (- 1)$
$= 0.34 - 0.02955 = 0.31045 v o l t$ .

Calculate the electrode potential at a copper electrode dipped in a 0.1 M solution of copper sulphate at 25∘C. The standard electrode potential of Cu2+/Cu system is 0.34 volt at 298 K.

We know that, Ered=E∘red+0.0591nlog10[ion]Putting the values of E∘red=0.34 V,n=2 and [Cu2+]=0.1MEred=0.34+0.05912log10[0.1]=0.34+0.02955×(−1)=0.34−0.02955=0.31045 volt.

Calculate the electrode potential at a copper electrode dipped in a $0.1 M$ solution of copper sulphate at $25^{\circ} C$ . The standard electrode potential of $C u^{2 +} / C u$ system is $0.34 v o l t$ at $298 K$ .

We know that, $E_{r e d} = E_{r e d}^{\circ} + \frac{0.0591}{n} {log}_{10} [i o n]$
Putting the values of $E_{r e d}^{\circ} = 0.34 V, n = 2$ and $[C u^{2 +}] = 0.1 M$
$E_{r e d} = 0.34 + \frac{0.0591}{2} {log}_{10} [0.1]$
$= 0.34 + 0.02955 \times (- 1)$
$= 0.34 - 0.02955 = 0.31045 v o l t$ .