$$[Ag^+]=0.002M$$
$$[Ni^{2+}]=0.160M$$
$$n=2$$
According to Nernst equation:
$$E_{cell}=E^0-\dfrac{0.0591}{2}\log \dfrac{[Ni^{2+}]}{[Ag^+]^2}$$
$$\therefore E_{cell}=1.05-\dfrac{0.0591}{2}\log \dfrac{0.160}{(0.002)^2}$$
$$\therefore E_{cell}=1.05-0.02955\, \log{(4\times 10^4)}$$
$$\therefore E_{cell}=0.91V$$