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Standard XII
Physics
Question

Calculate the heat required to convert 3kg of ice at −12oC kept in a calorimeter to steam at 100o at atmospheric pressure. (Given: specific heat of ice =2.100×105Jkg−1K−1, specific heat of water =4.186×106Jkg−1, latent heat of fusion of ice =3.35×105Jkg−1 and latent heat of steam =2.256×106Jkg−1) .

  1. 11.1×106J
  2. 9.1×106J
  3. 7.1×106J
  4. 9.9×106J

A
9.9×106J
B
11.1×106J
C
9.1×106J
D
7.1×106J
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Similar Questions
Q1
Calculate the heat required to convert 3kg of ice at −12oC kept in a calorimeter to steam at 100o at atmospheric pressure. (Given: specific heat of ice =2.100×105Jkg−1K−1, specific heat of water =4.186×106Jkg−1, latent heat of fusion of ice =3.35×105Jkg−1 and latent heat of steam =2.256×106Jkg−1) .

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Q2

Calculate the amount of heat required to convert 1.00 kg of ice at -10°C
at normal pressure to steam at 100°C.

The specific heat capacity of ice=2100 Jkg−1K−1

Latent heat of fusion of ice=3.36×105 Jkg−1

The specific heat capacity of water=4200 Jkg−1K−1

Latent heat of vaporization of water=2.25×106 Jkg−1


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Q3
Calculate the amount of heat required to convert 1.00 kg of ice at −10∘C into steam at 100∘C at normal pressure. (Sice=2100 J kg−1K−1,
Swater=4200 J kg−1K−1,
Lf,ice=3.36×105 J kg−1,
Lv,water=2.25×106 J kg−1)
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Q4
A copper calorimeter of mass 100gm contains 200gm of a mixture of ice and water. Steam at 100∘C under normal pressure is passed into the calorimeter and the temperature of the mixture is allowed to rise to 50∘C. If the mass of the calorimeter and its contents is now 330gm, what was the ratio of ice and water in the beginning? Neglect heat losses.
Given: Specific heat capacity of copper =0.42×103Jkg−1K−1 ,
Specfic heat capacity of water =4.2×103Jkg−1K−1
Specific heat of fusion of ice =3.36×105Jkg−1
Latent heat of condensation of steam =22.5×105Jkg−1
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Q5

1 kg of ice at 0∘C is mixed with 1 kg of steam at 100∘C. What will be the composition of the system when thermal equilibrium is reached? Latent heat of fusion of ice = 3.36 × 105 J kg−1, specific heat capacity of water = 4200 J kg −1 K−1 and latent heat of vaporization of water = 2.26 × 106 J kg−1


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