In the given figure,
Given angle is $$110^{0}$$
$$p=\angle 1$$ (Vertically opposite angles)
But $$\angle 1+110^{0}=180^{0}$$ (Co-interior angles)
$$\Rightarrow \angle 1=180^{0}-110^{0}=70^{0}$$
$$\Rightarrow p=\angle 1=70^{0}$$
$$s=110^{0}$$ (Alternate angles with $$110^{0}$$)
$$p=q$$ (Corresponding angles)
$$q=70^{0}$$
$$r=q$$ (Alternate angles)
$$r=70^{0}$$
Now, $$p=70^{0},q=70^{0},r=70^{0},s=110^{0}$$