Question

[Assume the density of water to be one]

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Updated on : 2022-09-05

Solution

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For dilute solutions, 1 L of water (or 1 L of solution) contains $181000 =55.55$ moles of water.

Let n be the number of moles of ethanol. The mole fraction of ethanol is 0.040.

Hence, $0.040=n+55.55n $

$n=0.040n+2.222$

$n=1−0.0402.222 =2.31$ moles.

The molarity of the solution is the ratio of the number of moles of solute present in 1 L of solution.

As 1 L of solution contains 2.31 moles of ethanol, the molarity of a solution is 2.31 M.

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