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Question

Calculate the perimeter of isosceles triangle.

$26 c m$
$13 c m$
$29 c m$
$15 c m$

A

13 c m

B

29 c m

C

26 c m

D

15 c m

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Solution

Verified by Toppr

$A = \frac{h_{b} b}{2} = \frac{8 \times 7}{2} = 28 c m^{2}$
$a = 11 c m = c$
$b = 7 c m$
$h = 8 c m$
Perimeter of the triangle = $a + c + 2 \frac{A}{h_{b}} = 11 + 11 + 2 \times \frac{28}{8} = 29$ cm

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