0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the pH of a 0.2 M solution of HCN.Dissociation constant of HCN$$=7.2\times10^{-10}$$

Solution
Verified by Toppr

Was this answer helpful?
1
Similar Questions
Q1
Calculate [H3O+],[OH] and pH of 0.2M solution of HCN. (Ka=7.2×1010)
View Solution
Q2
Calculate the pH of 0.01 M solution of NH4CN. The dissociation constants Ka for HCN=6.2×1010 and Kb for NH3=1.6×105.
View Solution
Q3
The concentration of HCN and NaCN in a solution is 0.01 M each. Calculate the concentration of hydroxyl ions if the dissociation constant of HCN is 7.2×1010.
View Solution
Q4
Calculate the degree of hydrolysis of 0.10 solution of KCN. Dissociation constant of HCN=7.2×1010 at 25oC and Kw=1.0×104
View Solution
Q5
The concentration of HCN and NaCN in a solution is 0.01M each. Calculate the concentrations of hydrogen and hydroxyl ions if the dissociation constant of HCN is 7.2×1010.
View Solution