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Question

Observe the figure showing the path of a body which started from $$A$$ and moved to $$C$$ through $$B$$.Calculate the speed of the body.

Solution
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Distance $$=AB+BC=60+40=100\ m$$Time $$=6s+4s=10\ sec$$$$\therefore$$ Speed $$=\dfrac{Distance}{Time}=\dfrac{100}{10}=10\ m/s$$

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