Observe the figure showing the path of a body which started from $$A$$ and moved to $$C$$ through $$B$$. Calculate the speed of the body.

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Solution

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Distance $$=AB+BC=60+40=100\ m$$ Time $$=6s+4s=10\ sec$$ $$\therefore$$ Speed $$=\dfrac{Distance}{Time}=\dfrac{100}{10}=10\ m/s$$

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