Calculate the temperature which the value in degrees celsius and degrees Fahernheit is same-

Question

Toppr Admin · Accepted Answer

The relationship between -circ-0 - and - -circ-F - is- -circ-C - -dfrac-5-9- -F - 32- -If - x -circ-C - x -circ-F- - then - x - -dfrac-5-9-x - 32- -or - 9x - 5x - 160 - or - 4x - - 160 -or - x - - 40-circ-C -Thus - - 40-circ-C - - 40-circ-F-

Calculate the temperature at which the value in degrees celsius and degrees Fahernheit is same.

The relationship between $$)^{\circ}0 $$ and $$ ^{\circ}F $$ is:

$$ ^{\circ}C = \dfrac{5}{9} (F - 32) $$

If $$ x ^{\circ}C = x ^{\circ}F, $$ then $$ x = \dfrac{5}{9}(x - 32) $$

or $$ 9x = 5x - 160 $$ or $$ 4x = - 160 $$

or $$ x = - 40^{\circ}C $$

Thus $$ - 40^{\circ}C = - 40^{\circ}F.$$

Calculate the temperature at which the value in degrees celsius and degrees Fahernheit is same.

The relationship between $$)^{\circ}0 $$ and $$ ^{\circ}F $$ is:$$ ^{\circ}C = \dfrac{5}{9} (F - 32) $$If $$ x ^{\circ}C = x ^{\circ}F, $$ then $$ x = \dfrac{5}{9}(x - 32) $$or $$ 9x = 5x - 160 $$ or $$ 4x = - 160 $$or $$ x = - 40^{\circ}C $$Thus $$ - 40^{\circ}C = - 40^{\circ}F.$$

The relationship between $$)^{\circ}0 $$ and $$ ^{\circ}F $$ is:

$$ ^{\circ}C = \dfrac{5}{9} (F - 32) $$

If $$ x ^{\circ}C = x ^{\circ}F, $$ then $$ x = \dfrac{5}{9}(x - 32) $$

or $$ 9x = 5x - 160 $$ or $$ 4x = - 160 $$

or $$ x = - 40^{\circ}C $$

Thus $$ - 40^{\circ}C = - 40^{\circ}F.$$