Question

Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm${}^3$ at 27 ${}^{\circ }C$. (R = 0.083 bar dm${}^3$ K${}^{-1}$ mol${}^{-1}$)

Answer 1

The partial pressure of oxygen is $P=\frac{nRT}{V}=\frac{8\times 0.083\times 300}{32\times 1}=0.225bar$.
The partial pressure of hydrogen gas is $P^{\prime }=\frac{n^{\prime }RT}{V^{\prime }}=\frac{2\times 0.083\times 300}{1}=49.8bar$.
Total pressure of the mixture$=6.225+49.8=56.025bar$.