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Question

Calculate the uncertainty in velocity of a cricket ball of mass $150 g$ if the uncertainty in its position is of the order of $1 \overset{˚}{A}$ $(h = 6.6 \times 10^{- 34} k g m^{2} s^{- 1})$ .

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Updated on : 2022-09-05

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$m = 150 \times 10^{- 3} k g Δ x = 10^{- 10} A^{0}$ h=planck's constant
Using Heisenburg Uncertainity Principle
$Δ x . m Δ v \geq \frac{h}{4 π} Δ v = \frac{h}{4 π m Δ x} Δ v = \frac{6 . 6 2 6 \times 1 0 ^{- 34}}{4 \times 3 . 1 4 \times 1 0 ^{- 10} \times 0 . 1 5} = 3.5 \times 10^{- 24} m s^{- 1}$

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