Calculate the value of dfrac-290 Ktimes 300-oC-0-oC- in Kelvin scale-708-6 K608-6 K508-6 K408-6 K

Question

Toppr Admin · Accepted Answer

Convert Celsius to kelvin-K-C-273-15For 3000C-K-300-273-15-xA0- -xA0- -xA0-573-15Putting these value in the equation-290-xD7-573-15273-15-166213-15273-15-608-6KHence- option B is correct-

Calculate the value of $\frac{(290 K \times 300^{o} C)}{0^{o} C}$ in Kelvin scale.
708.6 K
608.6 K
508.6 K
408.6 K

Convert Celsius to kelvin:
$K = C + 273.15$

For $300^{0} C$ -
$K = 300 + 273.15$

$= 573.15$

Putting these value in the equation:

$= \frac{290 \times 573.15}{273.15}$

. $= \frac{166213.15}{273.15}$

$= 608.6 K$

Hence, option B is correct.

Calculate the value of (290K×300oC)0oC in Kelvin scale.708.6 K608.6 K508.6 K408.6 K

Convert Celsius to kelvin:K=C+273.15For 3000C-K=300+273.15 =573.15Putting these value in the equation:=290×573.15273.15.=166213.15273.15=608.6KHence, option B is correct.

Calculate the value of $\frac{(290 K \times 300^{o} C)}{0^{o} C}$ in Kelvin scale.
708.6 K
608.6 K
508.6 K
408.6 K

Convert Celsius to kelvin:
$K = C + 273.15$

For $300^{0} C$ -
$K = 300 + 273.15$

$= 573.15$

Putting these value in the equation:

$= \frac{290 \times 573.15}{273.15}$

. $= \frac{166213.15}{273.15}$

$= 608.6 K$

Hence, option B is correct.