Calculate the volume occupied by 8-8 g of COdisplaystyle -2- 31-1displaystyle -circ-C and 1 bar pressure- -R - 0-083 bar L Kdisplaystyle -1- moldisplaystyle -1-

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Toppr Admin · Accepted Answer

The number of moles is n-8-844-0-2-The volume occupied is V-nRTP-V-0-2-xD7-0-083-xD7-304-11-5-05L

Calculate the volume occupied by 8.8 g of CO $_{2}$ at 31.1 $^{\circ} C$ and 1 bar pressure. (R = 0.083 bar L K $^{- 1}$ mol $^{- 1}$ )

The number of moles is $n = \frac{8.8}{44} = 0.2$ .

The volume occupied is $V = \frac{n R T}{P}$ .

$V = \frac{0.2 \times 0.083 \times 304.1}{1} = 5.05 L$

Calculate the volume occupied by 8.8 g of CO2 at 31.1∘C and 1 bar pressure. (R = 0.083 bar L K−1 mol−1)

The number of moles is n=8.844=0.2.The volume occupied is V=nRTP.V=0.2×0.083×304.11=5.05L

Calculate the volume occupied by 8.8 g of CO $_{2}$ at 31.1 $^{\circ} C$ and 1 bar pressure. (R = 0.083 bar L K $^{- 1}$ mol $^{- 1}$ )

The number of moles is $n = \frac{8.8}{44} = 0.2$ .

The volume occupied is $V = \frac{n R T}{P}$ .

$V = \frac{0.2 \times 0.083 \times 304.1}{1} = 5.05 L$